x^4-3x^2+12=0

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Solution for x^4-3x^2+12=0 equation:


Simplifying
x4 + -3x2 + 12 = 0

Reorder the terms:
12 + -3x2 + x4 = 0

Solving
12 + -3x2 + x4 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-12' to each side of the equation.
12 + -3x2 + -12 + x4 = 0 + -12

Reorder the terms:
12 + -12 + -3x2 + x4 = 0 + -12

Combine like terms: 12 + -12 = 0
0 + -3x2 + x4 = 0 + -12
-3x2 + x4 = 0 + -12

Combine like terms: 0 + -12 = -12
-3x2 + x4 = -12

The x term is -3x2.  Take half its coefficient (-1.5).
Square it (2.25) and add it to both sides.

Add '2.25' to each side of the equation.
-3x2 + 2.25 + x4 = -12 + 2.25

Reorder the terms:
2.25 + -3x2 + x4 = -12 + 2.25

Combine like terms: -12 + 2.25 = -9.75
2.25 + -3x2 + x4 = -9.75

Factor a perfect square on the left side:
(x2 + -1.5)(x2 + -1.5) = -9.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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